《微積分初步》形成性考核冊題解

1、１微積分初步形成性考核作業(yè)題解微積分初步形成性考核作業(yè)題解作業(yè)（一）作業(yè)（一）————函數(shù)，極限和連續(xù)一、填空題（每小題一、填空題（每小題2分，共分，共20分）1函數(shù)的定義域是：)2ln(1)(??xxf)3()32[???2函數(shù)的定義域是xxf??51)()5(??3函數(shù)的定義域是：24)2ln(1)(xxxf????]21()12(????4函數(shù)，則答案：72)1(2????xxxf?)(xf62?x5函數(shù)，則答案：???????0

2、e02)(2xxxxfx?)0(f26函數(shù)，則答案：xxxf2)1(2????)(xf12?x7函數(shù)的間斷點(diǎn)是答案：1322????xxxy1??x8答案：19若，則答案：2???xxx1sinlim2sin4sinlim0??kxxx?k10若，則答案：1.523sinlim0??kxxx?k二、單項(xiàng)選擇題（每小題二、單項(xiàng)選擇題（每小題2分，共分，共24分）分）1設(shè)函數(shù)，則該函數(shù)是（B）2eexxy???A奇函數(shù)B偶函數(shù)C非奇非偶函數(shù)

3、D既奇又偶函數(shù)2設(shè)函數(shù)，則該函數(shù)是（A）xxysin2?A奇函數(shù)B偶函數(shù)C非奇非偶函數(shù)D既奇又偶函數(shù)3函數(shù)的圖形是關(guān)于（D）對稱222)(xxxxf???AB軸C軸D坐標(biāo)原點(diǎn)xy?xy4下列函數(shù)中為奇函數(shù)是（無）ABCDxxsinxln)1ln(2xx??2xx?３2計(jì)算極限解165lim221????xxxx2716lim)1)(1()1)(6(lim165lim11221???????????????xxxxxxxxxxxx3解32

4、9lim223????xxxx324613lim)3)(1()3)(3(lim329lim33223????????????????xxxxxxxxxxxx4計(jì)算極限解4586lim224?????xxxxx3212lim)1)(4()2)(4(lim4586lim44224????????????????xxxxxxxxxxxxx5計(jì)算極限解6586lim222?????xxxxx234lim)2)(3()2)(4(lim6586li

5、m22222????????????????xxxxxxxxxxxxx6計(jì)算極限xxx11lim0???解)11()11)(11(lim11lim00???????????xxxxxxxx21111lim)11(lim00????????????xxxxxx7計(jì)算極限解xxx4sin11lim0???xxxxxxxxxxxx4sin)11(lim4sin)11()11)(11(lim4sin11lim000???????????????

6、?811214144sin1)11(1)41(lim4sin)11(44lim00?????????????????xxxxxxxx8計(jì)算極限解244sinlim0???xxx)24)(24()24(4sinlim244sinlim00???????????xxxxxxxx16414)24(44sin4lim)24(4sinlim00??????????????xxxxxxxx作業(yè)（二）作業(yè)（二）————導(dǎo)數(shù)、微分及應(yīng)用一、填空題（每小