密碼學(xué)實(shí)驗(yàn)報(bào)告

1、目錄AES AES 加密算法實(shí)現(xiàn) 加密算法實(shí)現(xiàn) .......................................... ..........................................2一． 一． 實(shí)驗(yàn)?zāi)康?實(shí)驗(yàn)?zāi)康?........................................ .........................................2二． 二． 實(shí)驗(yàn)原理

2、實(shí)驗(yàn)原理......................................... .........................................2三． 三． 實(shí)驗(yàn)步驟 實(shí)驗(yàn)步驟......................................... .........................................2四． 四． 實(shí)驗(yàn)結(jié)果 實(shí)驗(yàn)結(jié)果..................

3、....................... .........................................6五． 五． 實(shí)驗(yàn)心得 實(shí)驗(yàn)心得......................................... .........................................8六． 六． 源代碼： 源代碼：........................................

4、. .........................................9RSA RSA 加解密算法實(shí)現(xiàn) 加解密算法實(shí)現(xiàn) ....................................... .......................................18 18一． 一．實(shí)驗(yàn)?zāi)康?實(shí)驗(yàn)?zāi)康模?....................................... ............

5、............................18 18二． 二．實(shí)驗(yàn)要求： 實(shí)驗(yàn)要求：........................................ ........................................18 18三． 三．RSA RSA 函數(shù)主要代碼 函數(shù)主要代碼 .................................. .......................

6、...........18 18四．運(yùn)算結(jié)果顯示： 四．運(yùn)算結(jié)果顯示：.................................... ....................................21 21五．實(shí)驗(yàn)心得 五．實(shí)驗(yàn)心得.......................................... ..........................................21 21prin

7、tf(“\n 請(qǐng)輸入密鑰！\n“); for(i = 0;i <= 3;i ++)for(j = 0;j <= 3;j ++) {fscanf(fp,“%02x“,printf(“%02x “,keys[j][i]);}for(i = 4;i <= 43;i ++){ //make the other 40 keys if(i % 4 == 0){ //如果

8、能被 4 整除，特殊處理for(j = 1;j <= 4;j ++) //把前一個(gè)密鑰移位賦值給數(shù)組past[j - 1] = keys[j % 4][i -1];for(j = 0;j <= 3;j ++){if(j == 0)keys[j][i] = S_BOX[past[j] / 16][past[j] % 16] ^ Rcon[i / 4] ^ keys[j][i - 4];elseke

9、ys[j][i] = S_BOX[past[j] / 16][past[j] % 16] ^ keys[j][i - 4];}}else{for(j = 0;j <= 3;j ++){keys[j][i] = keys[j][i - 4] ^ keys[j][i - 1];}}}} 2. 2.字節(jié)變換 字節(jié)變換void bytesub(unsigned char S_BOX[][16],unsigned char B[][4])