激光原理與激光技術(shù)課后習(xí)題答案完整版及勘誤表

1、激光原理與激光技術(shù)習(xí)題答案激光原理與激光技術(shù)習(xí)題答案《激光原理與激光技術(shù)》堪誤表見(jiàn)下方《激光原理與激光技術(shù)》堪誤表見(jiàn)下方習(xí)題一習(xí)題一(1)為使氦氖激光器的相干長(zhǎng)度達(dá)到1m，它的單色性???應(yīng)為多大？解：10101032861000106328????????????.LRc(2)?=5000的光子單色性???=107，求此光子的位置不確定量?x解：??hp?????2hphpx???mRphx5101050007102?????????

2、?????(3)CO2激光器的腔長(zhǎng)L=100cm，反射鏡直徑D=1.5cm，兩鏡的光強(qiáng)反射系數(shù)分別為r1=0.985r2=0.8。求由衍射損耗及輸出損耗分別引起的?、?c、Q、??c(設(shè)n=1)解：衍射損耗:1880107501106102262.).(.aL??????????s..cLc881075110318801?????????686810113107511061010314322???????????????....QcMH

3、z.Hz...cc19101910751143212168?????????????輸出損耗:1190809850502121.)..ln(.rrln????????s..cLc881078210311901?????????686810964107821061010314322???????????????....QcMHz.Hz...cc75107510782143212168?????????????(4)有一個(gè)諧振腔，腔長(zhǎng)L=1

4、m，兩個(gè)反射鏡中，一個(gè)全反，一個(gè)半反，半反鏡反射系數(shù)r=0.99，求在1500MHz的范圍內(nèi)所包含的縱模個(gè)數(shù)，及每個(gè)縱模的線寬(不考慮其它損耗)解：MHzHz.Lcq150105112103288?????????11]11501500[]1[??????????qq005.0201.02???T?scLc781067.6103005.01?????????MHzcc24.01067.614.321217???????????(5)某固

5、體激光器的腔長(zhǎng)為45cm，介質(zhì)長(zhǎng)30cm，折射率n=1.5，設(shè)此腔總的單程損耗率0.01?，求此激光解：??hdtdP?shcPhPdtdP11051031063.610101198346????????????????(6)紅寶石調(diào)Q激光器中有可能將幾乎全部的Cr3激發(fā)到激光上能級(jí)，并產(chǎn)生激光巨脈沖。設(shè)紅寶石棒直徑為1cm，長(zhǎng)為7.5cm，Cr3的濃度為2?109cm3，脈沖寬度10ns，求輸出激光的最大能量和脈沖功率。解：JhLrV

6、hW9108341522103.4106943103106.631020.0750.0053.14??????????????????????wtWP34.01010104.399???????(7)靜止氖原子3S2?2P4譜線中心波長(zhǎng)0.6328?m，求當(dāng)它以0.1c速度向觀察者運(yùn)動(dòng)時(shí)，中心波長(zhǎng)變?yōu)槎啻?？解：mcccvz???5695.06328.09.06328.0)1.01(100???????????????(9)紅寶石激光器為

7、三能級(jí)系統(tǒng)，已知S32=0.5?1071sA31=3?1051sA21=0.3?1031s。其余躍遷幾率不計(jì)。試問(wèn)當(dāng)抽運(yùn)幾率W13等于多少時(shí)，紅寶石晶體將對(duì)?=0.6943?m的光是透明的？解：02123232???AnSndtdn?322123SAnn??03233131313????SnAnWndtdn?)(323113132331313SAnnnSnAnW?????透明即n1=n2175733231322132312313318)

8、105.0103(105.0103.0)()(?????????????sSASASAnnW習(xí)題三習(xí)題三(1)若光束通過(guò)1m長(zhǎng)的激光介質(zhì)以后，光強(qiáng)增大了一倍，求此介質(zhì)的增益系數(shù)。解：2lnln10??IIzG(2)計(jì)算YAG激光器中的峰值發(fā)射截面S32，已知??F=2?1011Hz?3=2.3?104sn=1.8。解：222114221223222032109.1102103.28.114.341006.14mnSF??????????