高考數(shù)學(xué)模擬試題第三部分

1、模擬試題第三部分模擬試題第三部分【試題答案】【試題答案】一.1.??fxgxexfxgxxxxxxxxxx()()lim()()limlim???????????????232120023202121，故選C。2.ffxfxxxxxx()lim()()lim()()()00012200300?????????……?????????()()()!1220032003……選C3.解：解：上的投影為：??ab在Paaabaabababbrjb

2、????????????????????????????????cos()1310243041222應(yīng)選B4.解：解：當(dāng)線性無關(guān)時(shí)，是方程的通解；當(dāng)yy12、cycy1122?yPyPy“???120yy12、線性相關(guān)時(shí)，不是通解，故應(yīng)選B。5.解：解：在處收斂，故冪級(jí)數(shù)的收斂半徑，收斂區(qū)間，axnnn???0x?2R?2??()22，而，故在處絕對(duì)收斂。?????????122，，RRaxnnn???1x??1故應(yīng)選C。二.6.解：解

3、：??????fxxxxxx()????????????14845524151222令得：ux??1fuuufxxx()()???????45245222??gxfeeegxeexxxxx()()????????????45285227.由limlimxxxxkkkkxkxeekk????????????????????????????????112112222，8.解：解：，故y在[1，5]上嚴(yán)格單調(diào)遞增，于是最小值是yxx()???

4、??55015，，要使在處連續(xù)，應(yīng)有fx()x?1kffxx????()lim()11118.解：解：，切線的斜率為yeexyexex?????112，kyex???12切線方程為：，即??yeex????2121yex??2119.是的原函數(shù)xx2?fx()?????????fxxfx212xfxdxxdxx()010120121?????20.解：解：?????????????????zxxxeyexeyzxyyzxxeyxxxx?

5、???????????sinsincos，21???????????zyxeyzyxxxeyxeyxxx????coscoscos，2121.的法向量為，的法向量?1???n1121?，，?2???n2211??，，所求平面與都垂直，故的法向量為???12、??????????nnnijkijk???????1212121135所求平面又過點(diǎn)，故其方程為：??M0111，，???????1131510???????xyz即：xyz???